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Searches for the last occurrence of a subrang
Key Facts
Gyroscopic Couple: The rate of change of angular momentum (= Moment of Inertia.
= Angular velocity
= Angular velocity of precession.
Blaise Pascal (1623-1662) was a French mathematician, physicist, inventor, writer and Catholic philosopher.
Leonhard Euler (1707-1783) was a pioneering Swiss mathematician and physicist.
Definition
The find_end() algorithm is defined in the standard header <algorithm> and in the nonstandard backward-compatibility header <algo.h>.Interface
#include <algorithm> template < class ForwardIterator1, class ForwardIterator2 > ForwardIterator1 find_end( ForwardIterator1 first1, ForwardIterator1 last1, ForwardIterator2 first2, ForwardIterator2 last2 ); template < class ForwardIterator1, class ForwardIterator2, class Pr > ForwardIterator1 find_end( ForwardIterator1 first1, ForwardIterator1 last1, ForwardIterator2 first2, ForwardIterator2 last2, BinaryPredicate comp );Parameters:
| Parameter | Description |
|---|---|
| first1 | A forward iterator addressing the position of the first element in the range to be searched |
| last1 | A forward iterator addressing the position one past the final element in the range to be searched |
| first2 | A forward iterator addressing the position of the first element in the range to be searched |
| last2 | A forward iterator addressing the position one past the final element in the range to be searched |
| comp | User-defined predicate function object that defines the condition to be satisfied if two elements are to be taken as equivalent. A binary predicate takes two arguments and returns true when satisfied and false when not satisfied |
Description
Find_end fi nds the last subsequence (elements betweenfi rst2 and last2) contained into a sequence (elements between first1 and last1 ).Return Value
Returns a forward iterator addressing the position of the first element of the last subsequence that matches the specified sequence or that is equivalent in a sense specified by a binary predicate.Complexity
The complexity is linear, find_end performs at most(last1 - first1) * (last2 - first2) comparisons.References
Example:
Example - find_end function
Problem
This program illustrates the use of the STL find_end() algorithm (default version) to find the last occurrence of one range of integer values in a vector within another range of integer values, also in a vector.
Workings
#include <iostream> #include <vector> #include <algorithm> using namespace std; int main() { int a1[] = {1, 2, 3, 4, 5, 6, 7, 8, 3, 4, 5, 9, 10, 11}; vector<int> v1(a1, a1+14); cout <<"\nHere are the contents of v1:\n"; for (vector<int>::size_type i=0; i<v1.size(); i++) cout <<v1.at(i)<<" "; int a2[] = {3, 4, 5}; vector<int> v2(a2, a2+3); cout <<"\nHere are the contents of v2:\n"; for (vector<int>::size_type i=0; i<v2.size(); i++) cout <<v2.at(i)<<" "; vector<int>::iterator p; p = find_end(v1.begin(), v1.end(), v2.begin(), v2.end()); if (p != v1.end()) cout <<"\nThe last instance of v2 in v1 begins at location " <<(int)(p-v1.begin()+1)<<"."; else cout <<"\nNo instance of v2 was found in v1."; return 0; }
Solution
Output:
Here are the contents of v1:
1 2 3 4 5 6 7 8 3 4 5 9 10 11 Here are the contents of v2:
3 4 5 The last instance of v2 in v1 begins at location 9.
1 2 3 4 5 6 7 8 3 4 5 9 10 11 Here are the contents of v2:
3 4 5 The last instance of v2 in v1 begins at location 9.
References