memmove

Copy byte string

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Contents

Interface
Description
Return Values
See Also
Standards
Page Comments

Interface

#include <string.h>void  memmove (void *dst, const void *src, size_t len)

Description

The memmove function copies \c len bytes from string \c src to string \c dst. The two strings may overlap; the copy is always done in a non-destructive manner.

Example:

Example - Copy byte string

Workings

#include <stdio.h>
#include <string.h>
int main()
{
  // define the array u
  int u[6] = {1, 2, 3, 4, 5};
  // copy u to u + 1 (these arrays overlap)
  memmove(u + 1, u, 5*sizeof(int));
  // display u
  for (int i = 0; i < 6; ++i)
    printf("u[%d] = %d\n", i, u[i]);
  return 0;
}

Solution

Output:

u[0] = 1
u[1] = 1
u[2] = 2
u[3] = 3
u[4] = 4
u[5] = 5

Return Values

The memmove function returns the original value of \c dst.

Standards

The memmove function conforms to ISO/IEC 9899:1990 ("ISO C90").