Rising Factorial

Calculates the rising factorial with arguments \e x and \e n.

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Interface
Rising Factorial
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Interface

C++

Rising Factorial

doublerising_factorial(	double	`x`
	int	`n`	)

The rising factorial has the following formula

$[x]^n = \prod_{k = 0}^{n - 1} (x + k)$

(1)

Note that the number of ways of arranging n objects in m ordered boxes is $\inline [m]^n$ . (Here, the ordering in each box matters). Thus, 2 objects in 2 boxes have the following 6 possible arrangements:

$-/12 \qquad 1/2 \qquad 12/- \qquad -/21 \qquad 2/1 \qquad 21/-$

(2)

Moreover, the number of non-decreasing maps from a set of n to a set of m ordered elements is $\inline [m]^n / n!$ . Thus the set of nondecreasing maps from $\inline (1,2,3)$ to $\inline (a,b,c,d)$ is the 20 elements:

$aaa \quad abb \quad acc \quad add \quad aab \quad abc \quad acd \quad aac \quad abd \quad aad$

(3)

$bbb \quad bcc \quad bdd \quad bbc \quad bcd \quad bbd \quad ccc \quad cdd \quad ccd \quad ddd$

(4)

Example:

#include <codecogs/maths/discrete/combinatorics/arithmetic/rising_factorial.h>
#include <iostream>
int main()
{
  std::cout << Maths::Combinatorics::Arithmetic::rising_factorial(5, 3) << std::endl;
  return 0;
}

Output:

References:

SUBSET, a C++ library of combinatorial routines, http://www.csit.fsu.edu/~burkardt/cpp_src/subset/subset.html

Parameters

x	the first rising factorial argument
n	the second falling factorial argument

Returns

the rising factorial of the pair of values x and n

Authors

Lucian Bentea (August 2005)

Source Code

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Last Modified: 5 Feb 11 @ 10:22 Page Rendered: 2022-03-14 15:00:10